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Answer :

`T//8` or `pi/(4omega)`Solution :

`I_(1)=I_(0)sin omega t_(1)` <br> `I_(0)=I_(0)sin omega t_(1)` <br> `t_(1)=(pi//2)/(2pi//T)=T/4` <br> & `I_(2)=I_(0)/sqrt2=I_(0) sin (omega t_(2))` <br> `t_(2)=(pi//4)/(2pi//T)=T/8` <br> `Deltat=t_(1)-t_(2)=T/4-T/8=T/8`